Question

Find the size, nature and position of image formed when an object of size 1 cm is placed at a distance of 15 cm from a concave mirror of focal length 10cm. ​

Answer 1

Ho,the height of the object =1cm,u=-15cm,f=-10cm

By mirrors formula,

1/f=1/v+1/u

1/-10=1/v-1/15

1/-10+1/15=1/v

-15+10/150=1/v

-5/150=1/v

-1/30=1/v

v=-30

m=Hi/Ho=v/u

Hi=Hoxv/u=1x-30/-15=2cm

The size of the image is 2 cm.It is erect and virtual.It is enlarged.

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