Find the size, Nature and position of images when
a. m=-1
b. m<+1
c.m<-1
d. m>-1
e. m>+1
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Answer:
u=−15cm
f=−10cm
h=1cm
From mirror formula
f1=u1+v1
v1=f1−u1
v1=−101−−151
v=−30cm
The image is formed at a distance 30cm on the left side of the mirror from the pole.
m=hh′=u−v
h′=−1×−15−30
h=−2cm
The image size is 2cm and it is real and inverted.
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