Find the size,nature and position of the image formed when an object of 1cm height is placed at a distance of 15cm from a concave mirror of focal length 10cm.
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Here we have H 1 as 1 cm, The distance of the image formed is given as -15 cm.
And the focal length of the object is given as -10 CM.
On applying the lens formula and putting the above given values of you and if we get we or distance of the object as:-
1/v + 1/u = 1/f
⇒ v= -30 cm
Now since we get the value of v as -30.
We can calculate the magnification of the object we get by applying the formula, m = H2/H1H = -v/u.
⇒30/-15
⇒H2 = 2
So from the answers in solutions,
We get we can figure out that the image formed will be real Diminished and inverted.
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