Find the size nature and position of the image formed when an object of size is 1 cm is placed at a distance of 15cm from a concave mirror of focal length 10cm
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Answer:
I suck at physics
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Explanation:
Concave mirror:
u = -15 cm, f = -10 cm, v =?
Mirror formula : 1/u + 1/v = 1/f
1/-15 +1/v = 1/-10
1/v = -1/10 +1/15 =( -3 +2)/30 = -1/30
v = -30 cm
Magnification, m = -v/u = -(-30)/-15 = -2
Now, h2/h1 = m
h2 = h1×m = 1 ×-2 = -2 cm
The image size is 2cm and it is real and inverted.
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