Math, asked by ms7637655, 2 months ago

find the size of class interval 0-15,15- 30 etc.​

Answers

Answered by pulakmath007
16

SOLUTION

TO DETERMINE

The size of class interval 0-15,15- 30 etc.

CONCEPT TO BE IMPLEMENTED

CLASS INTERVAL

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

CLASS BOUNDARY

When class intervals are such a type that the upper class limit of any class is not equal to lower class limit of successive class then to get any continuous graphical representation of the data it is sometimes required to rearrange the class limits in such a way that the upper class limit of any class coincides with the lower class limit of next class. Then these class limits are called class boundaries. The lower and upper ends of any class are called lower and upper class boundaries respectively.

CLASS LENGTH

Length of the class interval of an class is defined to be the difference between the lower and upper class boundaries ( not class limits) of that particular class interval.

Class length = Upper Class boundary - Lower class boundary

EVALUATION

Here the given class interval 0-15 , 15- 30

So class size

= Upper Class boundary - Lower class boundary

= 15 - 0

= 15

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Answered by lodhiyal16
4

Answer:

Step-by-step explanation:

class marks or class interval is the size of the class limit. Lower limit shows the  lowest term of that class like 0 -15 ,

0 is the lower class limit and 15 is the upper limit, but in 15 - 30 , 15 is the lower limit and 30 is upper limit.

It is defined as the difference between the upper-class limit and the lower class limit.

Class Interval = Upper-Class limit – Lower class limit.

The data is arranged into different classes and the width of such class is called class interval.

You can find the class interval or class marks as =upper limit - lower limit

In first class 0 -15

Putting value in formulae

= 15 - 0

= 15

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