Find the size of the abgle of a parallelogram if one angle is 20 degree less than twice the smallest angle.
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Answer:
let the smallest angle be x°
then the other angles will be (2x-20)°
we know that the adjacent angles of llgm are
supplementary
therefore,
x+2x-20=180
3x=180+20
3x=200
x=200/3
x=66.6°
other angle =2×66.6.-20=113.3°
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