Question

Find the size of the angle of a parallelogram if one angle is 20 less than the twice of the smallest

Answer 1

let the angle be x.

then the second angle will be 2x-20

So,

 x + 2x-20=180

 3x=200

x=200/3

x=66.66 degrees

Second angle = 2 *  66.66 - 20

                         = 113.32


Hope this helps!

Answer 2

Let the smallest angle be x
then,
the other angle must be 2x - 20

as we know that opposite angles of a parallelogram are equal and sum of all angle must equal 360°.
so,
2x - 20 + 2x - 20 + x + x = 360
6x = 400
x = 400/6
= 66.6°

so, two of the angles measure 66.6°
and the other measure 2 (66.6)- 20 = 113.2°