Question

find the size of the angles of a parallelogram if one angle is 20 degree less than twice the smallest angle​

Answer 1

given: one angle is 20 degree less than twice the small angle.

Let the smallest angle be 'x'.

we know that opposite angles are =.

so,the angle is (2x-20)°

2(2x-20)°+2x°=360°

4x-40°+2x°=360°

6x-40°=360°

6x=360°-40°

6x=320°

x=320/6

x=60°

therefore,the smallest angle is 60°.

then the largest angle is

(2×60-20)°

=(120-20)°

=100°

Therefore,the smallest angle is 60° and the largest angle is 100°.

Answer 2

Answer:

this answer is perfect wright