find the sizes of angle of parallelogram if one angle is 20°less than twice the smallest angle
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Smaller angle= x
Greater angle = 2x-20
Sum of angle of parallelogram = 360°
2(smaller angle) +2(greater angle)=360°
2x+2(2x-20)=360°
6x=360°+40°
6x=400°
x=400°/6=
Greater angle = 2x-20
Sum of angle of parallelogram = 360°
2(smaller angle) +2(greater angle)=360°
2x+2(2x-20)=360°
6x=360°+40°
6x=400°
x=400°/6=
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