Question

find the sizes of angles of parallelogram if one angle is 20° less than twice the smallest angle

Answer 1

HEYA MATE, HERE IS UR ANSWER __________________

Let the smallest angle be x degrees.

Then the angle given = 2x-20

We know that the opposite angles are equal

Therefore


<1+<2+<3+<4=360 ( angle sum property of a quadrilateral )

x+2x-20+x+2x-20=360

6x-40=360

6x=360+40

6x=400

x=400/6

x=66.7 (approx )

Therefore the smallest angle =66.7

Another angle =2×66.7-20

=113.4


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Answer 2

Let the smallest angle be x degrees.

Then the angle given = 2x-20

We know that the opposite angles are equal

Therefore

<1+<2+<3+<4=360 ( angle sum property of a quadrilateral )

x+2x-20+x+2x-20=360

6x-40=360

6x=360+40

6x=400

x=400/6

x=66.7 (approx )

Therefore the smallest angle =66.7

Another angle =2×66.7-20

=113.4

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