Math, asked by seema9472kumari, 3 months ago

Find the sizes of the angles of a parallelogram if one angle is 20° less than twice the smallest angle​

Answers

Answered by usjadhav2001
0

Answer:

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Step-by-step explanation:

let smallest angle be x°

then the other will be (2x-20)° we know that adjacent angles of llgm are

supplementary therefore,

x + 2x-20=180

3x=180+20

3x=200

x=200/3

x=66.6°

other angle =2x 66.6. -20= 113.3°

Answered by rosebabu630gmailcom
0

Answer:

Let the smallest angle be x

o

.

Then, the other angle will be (2x−20)

o

.

W e know that, sum adjacent angles of parallelogram are supplementary.

∴ x+(2x−20

o

)=180

o

⇒ 3x−20

o

=180

o

⇒ 3x=200

o

⇒ x=

3

200

o

∴ x=66.7

o

⇒ Other angle =2×66.6

o

−20

o

=113.3

o

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