Question

find the sizes of the angles of a parallelogram if one angle is 20° less than twice the smallest angle​

Answer 1

Step-by-step explanation:

let smallest angle be xº then the other will be (2x-20)° we know that adjacent angles of Ilgm are

therefore,

x + 2x - 20 = 180

supplementary x=66.6°

3x = 180 + 20

3x = 200

x = 200/3

other angle =2x 66.6. -20= 113.3°