Question

Find the sizes of the angles of a parallelogram if one angle is 20 less than twice the smallest angle?? ​

Answer 1

Answer:

Step-by-step explanation:

let the the smallest angle be x 

than the other angle = 2x - 20

as we know in parallelogram the angle opposite sides are equal we can say that the angles of the parallelogram are=

x,2 x-20,x ,2 x-20

the sum of all the angles are 360 in a parallelogram

so, x+2 x-20+x+2 x-20=360

6x -20 = 360

6x=360+40

6 x = 400

x =400/6

x = 66 2/3 (when we simplify 4/6)

2 x -20 = (66 2/3 ×2) - 20

2x - 20 = 113 1/3

∴ the angles are 66 2/3 ,113 1/3 , 66 2/3 ,113 1/3 ( ans