Question

Find the slant height of a cone of height 3cm and the diameter of it’s base is8cm.​

Answer 1

Answer:

5cm

Step-by-step explanation:

Slant Height(l)= √h²+r²

here r =8/2=4cm

√9+16=√25=5cm

Answer 2

Given :

The height of the cone = 3 cm

The diameter of its base = 8 cm

To find :

The slant height of the cone.

Solution :

The slant height of the cone is given by

$\boxed{ \bf l = \sqrt{ {h}^{2} + {r}^{2} } }$

where,

• l = slant height
• h = height
• r = radius

by substituting the values in the formula,

$\dashrightarrow \sf l = \sqrt{ {h}^{2} + {r}^{2} }$

$\dashrightarrow \sf l = \sqrt{ {3}^{2} + {4}^{2} }$

$\dashrightarrow \sf l = \sqrt{9 + 16 }$

$\dashrightarrow \sf l = \sqrt{25}$

$\dashrightarrow \bf l = 5 \: cm$

Thus, the slant height of the cone is 5 cm

Some formulas related to cones

$\diamondsuit \: \: \sf volume \: of \: the \: cone \: = \dfrac{1}{3} \pi {r}^{2} h$

$\diamondsuit \: \: \sf CSA \: of \: the \: cone \: = \pi rl$

$\diamondsuit \: \: \sf TSA \: of \: the \: cone \: = \pi rl + {\pi r}^{2}$