Question

find the slant height of a right circular cone whose height is 3.5 m and base radius is 12m​

Answer 1

Answer:

12.5 cm

Step-by-step explanation:

Apply the Pythagoras theorem as

l=√h^2+r^2

√ (3.5)^2+(12)^2

12.25+144= √156.25

l= 12.5

Answer 2

Given :

• Height of Cone is 3.5m
• Radius of Cone is 12m.

To Find :

• Slant Height of Cone.

Solution :

$\longmapsto\tt{Radius=12m}$

$\longmapsto\tt{Height=3.5m}$

For Slant Height :

$\longmapsto\tt\bold{{l}^{2}=\sqrt{{(h)}^{2}+{(r)}^{2}}}$

$\longmapsto\tt{l=\sqrt{{(3.5)}^{2}+{(12)}^{2}}}$

$\longmapsto\tt{l=\sqrt{12.25+144}}$

$\longmapsto\tt{l=\sqrt{156.25}}$

$\longmapsto\tt\bold{l=12.5cm}$

So , The slant height of the cone is 12.5cm..

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• C.S.A of Cone = πrl
• T.S.A of Cone = πrl(l+r)
• Volume of Cone = 1/3 πr²h
• Slant Height of Cone = √r² + h²

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