find the slop of the line which passes through origin and also passes through point (2,3)
Answers
Answered by
0
Answer:
The slope-intercept form of the equation of the line is
y
=
m
x
+
b
where
m
=
slope and
b
=
the y intercept
m
=
y
2
−
y
1
x
2
−
x
1
The given points are the origin
(
0
,
0
)
and (-3,6)
x
1
=
0
y
1
=
0
x
2
=
−
3
y
2
=
6
m
=
6
−
0
−
3
−
0
m
=
6
−
3
m
=
−
2
Now use the point slope formula to solve for the equation of the line.
(
y
−
y
1
)
=
m
(
x
−
x
1
)
For this situation we are given the slope of
3
and a point of
(
2
,
1
)
m
=
−
2
x
1
=
0
y
1
=
0
(
y
−
y
1
)
=
m
(
x
−
x
1
)
(
y
−
0
)
=
−
2
(
x
−
0
)
y
=
−
2
x
Similar questions