Find the slope and intersept of root 3x (1-root3) y=3
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Answer:
slope, m=\frac{-\sqrt{3}}{1-\sqrt{3}}m=
1−
3
−
3
y-intercept, c=\frac{3}{1-\sqrt{3}}c=
1−
3
3
Step-by-step explanation:
Find the slope and y intercept of
√3x+(1-√3)y= 3
Equation of given line is
\sqrt{3}x+(1-\sqrt{3})y=3
3
x+(1−
3
)y=3
\implies\:(1-\sqrt{3})y=-\sqrt{3}x+3⟹(1−
3
)y=−
3
x+3
\implies\:y=\frac{-\sqrt{3}}{1-\sqrt{3}}x+\frac{3}{1-\sqrt{3}}⟹y=
1−
3
−
3
x+
1−
3
3
comparing this with
\boxed{\bf{y=mx+c}}
y=mx+c
we get
slope, m=\frac{-\sqrt{3}}{1-\sqrt{3}}m=
1−
3
−
3
y-intercept, c=\frac{3}{1-\sqrt{3}}c=
1−
3
3
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