Math, asked by Riyu2425, 10 months ago

Find the slope and intersept of root 3x (1-root3) y=3

Answers

Answered by sujatakumari30071978
1

Mark as BRAINLIESTanswer

Answer:

slope, m=\frac{-\sqrt{3}}{1-\sqrt{3}}m=

1−

3

3

y-intercept, c=\frac{3}{1-\sqrt{3}}c=

1−

3

3

Step-by-step explanation:

Find the slope and y intercept of

√3x+(1-√3)y= 3

Equation of given line is

\sqrt{3}x+(1-\sqrt{3})y=3

3

x+(1−

3

)y=3

\implies\:(1-\sqrt{3})y=-\sqrt{3}x+3⟹(1−

3

)y=−

3

x+3

\implies\:y=\frac{-\sqrt{3}}{1-\sqrt{3}}x+\frac{3}{1-\sqrt{3}}⟹y=

1−

3

3

x+

1−

3

3

comparing this with

\boxed{\bf{y=mx+c}}

y=mx+c

we get

slope, m=\frac{-\sqrt{3}}{1-\sqrt{3}}m=

1−

3

3

y-intercept, c=\frac{3}{1-\sqrt{3}}c=

1−

3

3

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