Find the slope and they intercept of the line : 2x-3y+5
Answers
Answer:
2x+3y+5=0 is in General Slope form now put it into Slope form y=mx +b
3y +2x + ( ➖2x) +5 + ( ➖ 5) = 0 ➖2x ➖5 subtracting 2x and 5 from the left side of the equation let's do that to the right side as well
3y = - 2x - 5 we have to isolate y. Now ➗ left side of the equation and ➗ the right side as well by 3
3y/3 = - 2x/3 - 5/3 rewrite into Slope Form y=mx +b m = slope = rise/run= Δy/ Δx = (y2 - y1) /(x2-x1)
y = - 2/3x - 5/3
∴ recognizing slope = m = - 2/3 and b = - 5/3 = 1.6666666
Now solve for the y-intercept, so let is x = 0
y = - 2/3(0) - 5/3
y = - 5/3
∴ y = - 5/3 = b = y-intercept. When x equals zero then y equals - 5/3 or (0,-5/3). Now find that point and mark it on your graph
Now solve for x-intercept, so let y = 0
y = - 2/3x - 5/3
0 = - 2/3x - 5/3 multiply everything by 3 to cancel out the denominators
(3)0 = - (3)2/3x - (3)5/3
0 = - 2x - 5
-2x - 5 = 0
-2x = 5 now ➗ both sides by - 2 now to isolate x
2x/-2 = 5/-2 solve
x = - 5/2 ∴ x - intercept is = - 5/2 = - 2.5
slope = m = - 2/3
x - intercept = - 5/2 = - 2.5 when y = 0
y-intercept or b = - 5/3 = - 1.666 when x = 0
Answer:
Step-by-step explanation: