Math, asked by kunwar483, 6 months ago

find the slope and y- intercept
x + 3y
+ 5 = 0​

Answers

Answered by rashisharma30
3

Step-by-step explanation:

The equation of any straight line can be written as y=mx+c, where m is its slope and c is its y - intercept.

x+3y+5=0 can be written as 3y=−x−5 or y=

3

−1

x−

3

5

Comparing this equation with the standard form of the equation, we get:

m=−

3

1

,c=−

3

5

Hence, slope of x+3y+5=0 is −

3

1

and y - intercept is −

3

5

Answered by diyakhrz12109
3

Answer:

The equation of any straight line can be written as y=mx+c, where m is its slope and c is its y - intercept.

x+3y+5=0 can be written as 3y=−x−5 or y=  -1/3 x−  5/3

 

Comparing this equation with the standard form of the equation, we get:

m=−  1/3,c=−  5/3

Hence, slope of x+3y+5=0 is −31 and y - intercept is −35.  

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Step-by-step explanation:

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