find the slope and y- intercept
x + 3y
+ 5 = 0
Answers
Answered by
3
Step-by-step explanation:
The equation of any straight line can be written as y=mx+c, where m is its slope and c is its y - intercept.
x+3y+5=0 can be written as 3y=−x−5 or y=
3
−1
x−
3
5
Comparing this equation with the standard form of the equation, we get:
m=−
3
1
,c=−
3
5
Hence, slope of x+3y+5=0 is −
3
1
and y - intercept is −
3
5
Answered by
3
Answer:
The equation of any straight line can be written as y=mx+c, where m is its slope and c is its y - intercept.
x+3y+5=0 can be written as 3y=−x−5 or y= -1/3 x− 5/3
Comparing this equation with the standard form of the equation, we get:
m=− 1/3,c=− 5/3
Hence, slope of x+3y+5=0 is −31 and y - intercept is −35.
Step-by-step explanation:
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