Question

Find the slope and yinter cept of√3x+(1−√3)y=3​

Answer 1

Answer:

$m = \frac{ \sqrt{3} }{(1 - \sqrt{3} )} \: \: \: c = \frac{3}{(1 - \sqrt{3}) }$

Step-by-step explanation:

We Know That Slope Intercept Form Is

$y = mx + c$

Where, M Is The Slope Of Line And C Is The Y Intercept. Now We Have To Convert The Given Equation In The Form.

$(1 - \sqrt{3} )y = \sqrt{3} x + 3$

In Slope Intercept Form The Coefficient Of Y is 1. Therefore, We Need To Divide Each Term By The Coefficient Of Y.

$\frac{(1 - \sqrt{3})y }{(1 - \sqrt{3}) } = \frac{ \sqrt{3} x}{(1 - \sqrt{3}) } + \frac{3}{(1 - \sqrt{3} )}$

Therefore, Our Equation Becomes

$y = \frac{ \sqrt{3} x}{(1 - \sqrt{3}) } + \frac{3}{(1 - \sqrt{3} )}$

On Comparing With

$y = mx + c$

We Get

$m = \frac{ \sqrt{3} }{(1 - \sqrt{3} )}$

$c = \frac{3}{(1 - \sqrt{3} )}$