Question

Find the slope intercept form of the equation that passes through (-8, 4) and perpendicular to the line 8x - 2y= 0

Answer 1

Answer:

afhlgshllbxzhlnxshllvzzgb

Answer 2

✮ Given

» point ( -8 , 4 )

» Perpendicular to the line 8x-2y=0

✮ To find

» slope intercept form

✮ Solution

→ Slope intercept form :

y = mx + c

where x , y are the variables

m is the slope

c is the constant.

Given equation : 8x -2y = 0

2y = 8x + 0

here m = 8 ( slope A )

The other line is perpendicular point ( -8,4)

Let the other slope be B.

The slope is negatively inverse to the slope of A ( since its perpendicular )

So , B' slope = - 1/ A = - 1/8

y = mx + c ( -8 , 4 )

4 = (-1/8) *(-8) + c

4 = 1 + c

c = 3

So let us write the slope intercept form ,

y = - 1/8 x + 3

____________________