Find the slope of a
line parallel to
(613) (-4,5)
Answers
Step-by-step explanation:
Line L has a slope of 13/7. The line through which of the following pair of points is perpendicular to L
(-5,-7) (2,6)
(6,-5) (-7,2)
(-8,-7) (2,6)
(12, -3) (-7, 4)
Answer - 1
The slope of any line perpendicular to L must be -7/13.
The line through (6,-5) and (-7,2) has slope [2-(-5)]/(-7-6) = -7/13.
Answer - 2
You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:
m = (y2 - y1)/(x2 - x1)
Consider the second set of coordinates.
(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13
The second set of coordinates satisfy the condition.