Question

Find the slope of a line that passes through (12,12) with an intercept of x-intercept of 6.

Answer 1

Answer:

Answer:

y = -2x + 13

Step-by-step explanation:

Let the x-intercept = (x,0)

then y-intercept will be (0, 2x)

Calculating the slopes using the two points and point (5, 3)

(3-2x)/(5-0) = (0-3)/(x-5)

(3-2x)/5 = -3/(x-5)

(3-2x)(x-5)= -15

Expand and simplify:

-2x^2 + 13x = 0

x(-2x^2 + 13) = 0

Either x = 0, or x = 13/2

Slope of the line

= -3/(13/2 - 5)

= -2

Equation

(y-3)/(x-5) = 2

y= -2x + 13

Answer 2

Step-by-step explanation:

Answer:

Answer:

y = -2x + 13

Step-by-step explanation:

Let the x-intercept = (x,0)

then y-intercept will be (0, 2x)

Calculating the slopes using the two points and point (5, 3)

(3-2x)/(5-0) = (0-3)/(x-5)

(3-2x)/5 = -3/(x-5)

(3-2x)(x-5)= -15

Expand and simplify:

-2x^2 + 13x = 0

x(-2x^2 + 13) = 0

Either x = 0, or x = 13/2

Slope of the line

= -3/(13/2 - 5)

= -2

Equation

(y-3)/(x-5) = 2

y= -2x + 13