Find the slope of a line that passes through (12,12) with an intercept of x-intercept of 6.
Answers
Answer:
Answer:
y = -2x + 13
Step-by-step explanation:
Let the x-intercept = (x,0)
then y-intercept will be (0, 2x)
Calculating the slopes using the two points and point (5, 3)
(3-2x)/(5-0) = (0-3)/(x-5)
(3-2x)/5 = -3/(x-5)
(3-2x)(x-5)= -15
Expand and simplify:
-2x^2 + 13x = 0
x(-2x^2 + 13) = 0
Either x = 0, or x = 13/2
Slope of the line
= -3/(13/2 - 5)
= -2
Equation
(y-3)/(x-5) = 2
y= -2x + 13
Step-by-step explanation:
Answer:
Answer:
y = -2x + 13
Step-by-step explanation:
Let the x-intercept = (x,0)
then y-intercept will be (0, 2x)
Calculating the slopes using the two points and point (5, 3)
(3-2x)/(5-0) = (0-3)/(x-5)
(3-2x)/5 = -3/(x-5)
(3-2x)(x-5)= -15
Expand and simplify:
-2x^2 + 13x = 0
x(-2x^2 + 13) = 0
Either x = 0, or x = 13/2
Slope of the line
= -3/(13/2 - 5)
= -2
Equation
(y-3)/(x-5) = 2
y= -2x + 13