Question

find the slope of an verticle line 2x-3y+8=0​

Answer 1

Answer:

answers

Thus the equation of the line to be found (which would be perpendicular to 2x + 5y + 2 = 0 would be: y = (5/2)*x + c [ Equation of a straight line with slope

Answer 2

$\huge\bold\purple{Solution:}$

Since,

We know that,

$\small\fbox\pink{Slope→ y = mx+c}$

: . 2x-3y+8=0

: . 3y=2x+8

: . y=2/3x+8/3

Hence,Slope=m=2/3

$\small\fbox\orange{Hope itz help uh ♡}$