Question

find the slope of line perpendicular to x-3Y + 1=0

Answer 1

$x - 3y + 1 = 0 \\ m = 1 \div 3$
let the slope of perpendicular line be n
therefore mn=-1
$mn = - 1 \\ (1 \div 3)n = - 1 \\ n = - 3$
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