find the slope of normal to the curve y=x^3-x,x=2
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f'(x) = 3x²-1
put x=2 now
then slope = 3*2*2-1 = 12-1 = 11 is the answer
put x=2 now
then slope = 3*2*2-1 = 12-1 = 11 is the answer
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