Question

Find the slope of side BC of triangle ABC with vertices C(-3, 5), A(2, 3) and B(-4, -2)

Answer 1

∆∆SLOPE WILL BE 7.

Step-by-step explanation:

◆ A(2,3) ◆ B(-4,-2) ◆ C(-3,5)◆

Slope of BC of ∆ABC =

$\frac{5 - ( - 2)}{( - 3) - ( - 4)} \\ = \frac{5 + 2}{ - 3 + 4} \\ = \frac{7}{1} \\ = 7$

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