Question

Find the slope of tangent on the curve x²+y²-4x-1 = 0 at (3,2)​

Answer 1

Answer:

Given equation of the curve is

y=

x 3

3x+ 2

When

x=

3

,

y= (3)

3

− 9+ 2= 20

Therefore, the point on the curve is (3,20).

Differentiating equation 1 w.r.t. x, we get,

(

d x

d y

)= 3x

2

− 3

Therefore, the slope of the tangent at (3,20)

= 3(3)

3

− 3= 27− 3= 24