Question

find the slope of tangent to the curve y=3x^4-4x at the point whose x coordinate is 1​

Answer 1

Step-by-step explanation:

dy/dx = 4×3x^3‐4

dy/dx = 12x^3‐4

at x= 1

dy/dx = 12(1)^3‐4

dy/dx = 12‐4

dy/dx = 8