Question

find the slope of tangent to the curve y = f(x) it slope normal is 1/6​

Answer 1

Answer:

hope it's helpful to you

Step-by-step explanation:

Given, x=3t

2

+1,y=t

3

−1

Slope of the tangent to the given curve is

dx

dy

=

dt

dy

×

dx

dt

=3t

2

×

6t

1

=

2

t

Since the slope has to be calculated at x=1, i.e. at 3t

2

+1=1, we get t=0

Thus, the required slope is 0.