Find the slope of tangent to the curve y= x2 - 2x + 1 at (0,1)
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Answer:
Differentiating the equation of the curve with respect to x, we get
dx
dy
=2x−2
Since the tangent line is parallel to 2x−y+9=0,
dx
dy
=slope of the straight line=2
⇒2x−2=2
⇒x=2
Substituting x=2 in the equation of the curve, we get y=7
Hence, equation of tangent at (2,7) with slope 2 is
y−7=2(x−2)
⇒2x−y+3=0
Step-by-step explanation:
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2x-2
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