Find the slope of the curve y=2(1+3x)² at point (0,3)
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Answer:
x=0
y=2(1+3(0)^2
y=2(1+0)
y= 2+0
y=0
x=3
y=2(1+3x)^2
y=2(1+3(3))^2
y=2(1+27)
y=2+54
y=56
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