find the slope of the diagonals of a quadrilateral with vertices A(1,7) ,B(6,3),C(0,-3) and D(-3,3).
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In quadrilateral ABCD, AC and BD are the diagonals.
To find the slope of AC, A(X1,Y1)= (1,7) and C(X2,Y2)= (0,-3)
Therefore, Slope(m)= (Y2-Y1)/(X2-X1)
=(-3-7)/(0-1)
= -10/-1
= 10
In the same way, to find the slope of BD, B(X1,Y1)=(6,3) and D(X2,Y2)=(-3,3)
Therefore, Slope(m)= (Y2-Y1)/(X2-X1)
= (3-3)/(-3-6)
= 0/-9
=0
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