Question

find the slope of the line 2x + 5y - 11 = 0

Answer 1

$\text{We can find slope of a line in two different ways}$

$\textbf{1.\;y=mx+c form:}$

$2x+5y-11=0$

$\implies\;5y=-2x+11$

$\implies\;y=\frac{-2}{5}x+\frac{11}{5}$

$\text{Comparing this with y=mx+c, we get }$

$\textbf{Slope = }\bf\frac{-2}{5}$

$\textbf{2.Formula method:}$

$\textbf{Slope =}\frac{\textbf{-coefficient of x}}{\textbf{coefficient of y}}$

$\text{Slope = }\frac{-2}{5}$

Answer 2

Slope of the line 2x + 5y - 11 = 0 is -2/5

• Slope of a line is steepness of the line.
• Given line is

                  2x + 5y -11 = 0

                  2x + 5y = 11

                  5y = - 2x + 11

                  y = (- 2x + 11)/5

                 y = (-2/5)x + 11/5

• It is of the form

                  y = mx + c     (slope intercept form)

                  Where m = slope, c = intercept

• Comparing we get

                 m = -2/5, c = 11/5

∴ The slope of given line is -2/5