Question

find the slope of the line segment joining the points p(3.5,2.5)q(1.5,6)​

Answer 1

Answer:

SEE

Step-by-step explanation:

Perpendicular bisector = Cuts at mid point, and is perpendicular  

First find the mid point  

x coordinate = 1+4 / 2 = 2.5  

y coordinate = 5+6 / 2 = 5.5  

Mid point = (2.5, 5.5)  

Then find the slope of the bisector :  

Slope of the given line = (5-6) / (1-4) = 1/3  

Slope of given line multiplied by slope of bisector = -1  

Slope of bisector = -1 / (1/3)  

= -3  

Use the point slope form to find the bisector's formula :  

-3 = (5.5 - y) / (2.5 - x)  

-7.5 + 3x = 5.5 - y  

3x + y - 13 = 0  

Transform the formula into slope-intercept form  

3x + y - 13 = 0  

y = -3x + 13  

Because slope-intercept form is y = mx + c, where m is the slope and c is the y-intercept  

Therefore the perpendicular bisector cuts the y-axis at (0,13)  

Answer 2

Answer:

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