Question

Find the slope of the line that passes through points

(2,6) and (3,5).

a. 11/6
b. 1
c. -1
d. 11/5
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Answer 1

slope=(y2-y1)/(x2-x1),

slope =(5-6)/(3-2),


then

slope=-1/1,

=-1

Answer 2

$\text{When points are given, formula for getting slope is \: }\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$


In the question given points are ( 2 , 6 ) and ( 3 , 5 )


Here,
$x_{1}=2 \\ x_{2}=3 \\ y_{1}=6 \\ y_{2}=5$


Therefore,

$\text{slope of that line} = \dfrac{ 5 - 6 }{ 3 - 2 } \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 1}{1} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 1$




Thus,
slope of the line which passes through points ( 2 , 6 ) and ( 3 , 5 ) is - 1.