Question

find the slope of the line through each pair of points (6, -10) , (-15 , 15)​​

Answer 1

Answer:

Answer:

$\boxed{\boxed{\pink{\bf \leadsto The \ slope \ of \ the \ line \ is \ \dfrac{-25}{21}.}}}$

Step-by-step explanation:

Two points are given to us and we need to find the slope of the line . The slope of the line passing through points $\bf (x_1,y_1 ) \ \& \ (x_2,y_2)$ is given by ,

$\qquad\boxed{\red{\bf Slope = tan\theta=\dfrac{y_2-y_1}{x_2-x_1}}}$

Here , the points are ,

• ( 6 , -10 )
• ( -15 , 15 )

$\bf\implies Slope = \dfrac{y_2-y_1}{x_2-x_1}$

$\\\\\bf\implies Slope =\dfrac{15-(-10)}{-15-6}$

$\\\\\bf\implies Slope = \dfrac{15+10}{-21}\\\\\bf\implies Slope =\dfrac{-1(25)}{-1(-21)}\\\\ \bf\implies\boxed{\red{\bf Slope =\dfrac{-25}{21}}}$

★ Hence the slope of the line joining the two points is -25/21 .

Answer 2

Step-by-step explanation:

Answer:

Answer:

$\boxed{\boxed{\pink{\bf \leadsto The \ slope \ of \ the \ line \ is \ \dfrac{-25}{21}.}}}$

Step-by-step explanation:

Two points are given to us and we need to find the slope of the line . The slope of the line passing through points $\bf (x_1,y_1 ) \ \& \ (x_2,y_2)$ is given by ,

$\qquad\boxed{\red{\bf Slope = tan\theta=\dfrac{y_2-y_1}{x_2-x_1}}}$

Here , the points are ,

( 6 , -10 )

( -15 , 15 )

$\bf\implies Slope = \dfrac{y_2-y_1}{x_2-x_1}$

$\\\\\bf\implies Slope =\dfrac{15-(-10)}{-15-6}$

$\\\\\bf\implies Slope = \dfrac{15+10}{-21}\\\\\bf\implies Slope =\dfrac{-1(25)}{-1(-21)}\\\\ \bf\implies\boxed{\red{\bf Slope =\dfrac{-25}{21}}}$

★ Hence the slope of the line joining the two points is -25/21 .