Find the slope of the line which is perpendicular to x-y/2+3=0
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Since y= mx + c
Therefore, x- y/2 + 3= 0
2x-y+6=0
=> y= 2x + 6
Therefore slope of the given line is 2.
When lines are perpendicular,
product of slope are -1.
Therefore, 2 x m' = -1
m' = -1/2
So slope of line perpendicular to the given line is-1/2.
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