Question

Find the slope of the polar of (1, 3) with respect to the circle x square +y square -4x-4y-4=0 Also find the distance from the centre to it.

Answer 1

Step-by-step explanation:

Given Find the slope of the polar of (1, 3) with respect to the circle x square +y square -4x-4y-4=0 Also find the distance from the centre to it.  

• Now equation of the circle will be x^2 + y^2 – 4x – 4y – 4 = 0, centre C = (2,2)
• Now given Polar of (1,3) is 0
• Now the equation will be  
• So xx1 + yy1 – 4(x1 + x2 / 2) – 4(y1 + y2 / 2) – 4 = 0
• So x x 1 + y x 3 – 2(x + 1) – 2(y + 3) – 4 = 0
• So x + 3y – 2x – 2 – 2y – 6 – 4 = 0
• So – x + y – 12 = 0
• Or x – y + 12 = 0
• Now distance from the centre will be  
• C(2,2) = l – 2 + 2 – 12 / √1 + 1  l
•          = 12 / √2
•            = 3 √2

Reference link will be

https://brainly.in/question/6946906