Question

find the slope of the tangent line to y=f(x)
a. f(x) = x^2-3x+1
b. f(x) = 2x / x+1

Answer 1

a) y= F(X)

y=x^2-3x +1

slope of tangent=dy/dx

dy/dx=2x-3

Therefore, slope of tangent=2x-3

b)y= F(X)

y=2x/(x+2)

slope of tangent=dy/dx

dy/dx=[2(x+2)-2x(1)]/(x+2)^2

=4/(x+2)^2

Therefore, slope of tangent=4/(x+2)^2