Question

find the slope of the tangent of the curve y=1/x-1 at (3, 1/2)​

Answer 1

Step-by-step explanation:

f(x)=(x+1)(x−3)

Now

f(x)=0

⇒x=−1,x=3

Differentiating f(x) with respect to x

dx

dy

=x+1+x−3

=2x−2

=2(x−1)

Now slope of the tangent at (h,k) will be

dx

dy

h,k

Hence slopes of the tangent at x=−1 and x=3, will be

dx

dy

x=−1

=2(x−1)

x=−1

=−4

And

dx

dy

x=3

=2(x−1)

x=3

=4

Answer 2

Answer:

-1/4 is the write answer