Find the slope of the tangent on the curve y=x^3 at x=2.
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Answer:
heya mate.....
here is your answer
slope of the tangent on the curve can also be find with the help of differentiation.....
so just differentiate it and put the value of X as
dy/dx = d(x^3)/dx
..............= 3x^2.....
now put value of X in this
= 3× 2^2
= 3×4
= 12
aryan3664:
in maxima minima part here is a use of derivatives only therefore i was little bit confused. After all thanks a lot again
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