Question

Find the slope of the tangent to curve
$y = x {3} - x + 1$
at the point whose x's coordinate is 3

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Answer 1

Answer:

Step-by-step explanation:

the slope of the tangent to the curve

y = x^3 - x + 1  at the point with x coordinate x = 3  is equal to the value of the derivative of  y = x^3 - x + 1  at the point with x = 3.

y' = 3x^2 - 1

y'(3) = 3×3^2 - 1 = 3^3 - 1 = 27 - 1 = 26.

the slope is y'(3) = 26.