Find the slope of the tangent to curve y = x 3 − x + 1 at the point whose x-coordinate is 2.
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solution :- y = x³ - x + 1
we know, slope of tangent = value of 1st derivative of curve.
in mathematically, if f(x) is function.
then, slope of tangent of f(x) at (x = a)=
differentiate y with respect to x
slope of tangent = 11
we know, slope of tangent = value of 1st derivative of curve.
in mathematically, if f(x) is function.
then, slope of tangent of f(x) at (x = a)=
differentiate y with respect to x
slope of tangent = 11
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