Question

Find the slope of the tangent to the curve at the respective given points. y= x⁴+2x²-x at x=1​

Answer 1

The slope of the tangent at (x,y) is the value of (dy/dx) at (x1,y1) dy/dx = 4x3 + 4x - 1 dy/dx(at x = 1) = 4 + 4 - 1= 7 (i.e) slope of the tangent = 7 (ii) x = a cos3t, y = b sin3t Read more on Sarthaks.com - https://www.sarthaks.com/878632/find-the-slope-of-the-tangent-to-the-curves-at-the-respective-given-points-i-y-x-4-2x-2-x-at-x-

Step-by-step explanation:

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