Question

Find the slope of the tangent to the curve in the xy plane given by x = t2 + 3t - 8 , y = 2t 2 - 2t - 5 at t = 2.

Answer 1

Answer:

T=2

So,let's find x first.

x=t2+3t-8

x(2)=2(2)+3(2)-8

=4+6-8

=10-8

=2

Hence ,x=2

Let's find y now,

y(2)=2t2-2t-5

=2(2)2-2(2)-5

=8-4-5

=4-5

=-1

Hence ,y=-1

xy=2×(-1)

=-2.

Step-by-step explanation:

T=2

So,let's find x first.

x=t2+3t-8

x(2)=2(2)+3(2)-8

=4+6-8

=10-8

=2

Hence ,x=2

Let's find y now,

y(2)=2t2-2t-5

=2(2)2-2(2)-5

=8-4-5

=4-5

=-1

Hence ,y=-1

xy=2×(-1)

=-2.