Question

Find the slope of the tangent to the curve y = 2sin23x at x =
π
6
.

Answer 1

Answer:

ANSWER

y=2sin2(3x)

⇒dxdy=2×2sin(3x)×cos(3x)×3

(dxdy)x=6π=12×sin(2π)×cos(2π)

(dxdy)x=6π=12×1×0

(dxdy)x=6π=0