Find the slope of the tangent to the curve y=x^2-4x+5 at x=-2l
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The given line is 2y+x=7.
Slope of the above line =2−1
Thus the slope of the line tangent perpendicular to above line is 2.
The given curve,
y=x2−4x+5...(i)
Slope is given by y′.
Differentiate (i) with respect to x.
y′=2x−4
Equate this slope to 2.
Thus,
y′=2x−4=2⇒x=3
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