find the slope x intercept and y intercept of the line 3x–4y+11=0
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Equation of a line is 3x−4y+10=0. Find its
(i) slope,
(ii)x− and y- intercepts.
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given equation of line is
3x−4y+10=0
rewriting in general form
4y=3x+10
or
y=
4
3
x+
4
10
…(1)
and we know that general form a straight line is
y=mx+c …(2)
where m is slope of the line and c is the y-intercept of the line
hence, by comparing eq(1) and eq(2) we get
slope of line m=
4
3
(slope of line)
and y-intercept is defined as value of y at x=0
hence, from equation (1)
y=
4
3
×0+
4
10
or y=
4
10
(y-intercept)
and x-intercept is defined as value of x at y=0
hence, from equation (1) we get
0=
4
3
x+
4
10
3x=10
or x=−
3
10
(x-intercept)
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