Question

find the slopes of lines parallel to and perpendicular to the line joining (6,3),(-4,5)​

Answer 1

Answer:

hope it helps..... :)

MARK it as BRAINLIEST ☺️☺️

Answer 2

Concept Introduction: Slopes are a special part of Graphs.

Given:

We have been Given:

$(6 \: \: 3)( - 4 \: \: 5)$

To Find:

We have to Find: find the slopes of lines parallel to and perpendicular to the line joining the points.

Solution:

According to the problem,

$m1 = \frac{y2 - y1}{x2 - x1} \\ m1 = \frac{5 - 3}{ - 4 - 6} \\ m1 = - \frac{2}{10} \\ m1 = - \frac{1}{5}$

Now we know,

$m1 \times m2 = - 1 \\ - \frac{1}{5} \times m2 = - 1 \\ m2 = 5$

therefore the slopes are

$- \frac{1}{5} \: and \: 5$

Final Answer: The slopes are

$- \frac{1}{5} \: and \: 5$

#SPJ3